〰️ Matter Waves (de Broglie)

Dual nature, λ = h/p, accelerated electron, relativistic, phase & group velocity

λ = h/p λ ≈ 12.27/√V v_phase = c²/v
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💡 Dual nature & matter waves

de Broglie proposed that every particle has a wavelength λ = h/p = h/(mv). For an electron accelerated through potential V: λ = h/√(2meV); in Å with V in volts, λ ≈ 12.27/√V. Phase velocity of the matter wave is v_phase = c²/v (always > c); group velocity v_group = v (particle speed).

Matter wave calculators

λ from p or mv, accelerated electron, relativistic, phase & group velocity

Input
Momentum (p)
de Broglie wavelength
6.63 Å
Accelerating voltage (V)
Wavelength (electron)
1.23 Å
Input
Speed (v)
Rest mass (m₀)
Relativistic de Broglie λ
Particle speed (v)
Phase velocity (v_phase = c²/v)
Particle speed (v) = group velocity
Group velocity (v_group = v)
1×10⁶ m/s

〰️ Matter wave summary

Run a calculation to see result.
🧮Step-by-Step Solution▼ Show
Concept Formula Notes
de Broglie wavelength λ = h / p = h / (m v) p = momentum
Accelerated electron λ = h / √(2 m e V) V = accelerating voltage
λ (Å) for electron (V in volts) λ (Å) ≈ 12.27 / √V Useful numerical relation
Relativistic particle λ = h / √(2 m₀ c² (γ − 1)) γ = 1/√(1 − v²/c²)
Phase velocity v_phase = c² / v Always > c (de Broglie waves)
Group velocity v_group = v Equals particle velocity

About matter waves (de Broglie hypothesis)

de Broglie proposed that every particle with momentum p has an associated wavelength λ = h/p = h/(mv), showing wave-particle duality. For an electron accelerated from rest through potential V, kinetic energy K = eV, so λ = h/√(2meV). With V in volts, λ (Å) ≈ 12.27/√V.

Phase and group velocity

For de Broglie waves, the phase velocity is v_phase = c²/v (always greater than c); the group velocity is v_group = v, the particle speed. Only the group velocity carries energy and information.

Relativistic case

For relativistic particles, λ = h/√(2 m₀ c² (γ − 1)), where γ = 1/√(1 − v²/c²). This reduces to the non-relativistic form when v ≪ c.